1. I know I'll get told off for not using int void main() and return 0; but when I tried using them the program wouldn't compile at all. Now it runs but puts out a strange number (i.e. when I input 123 it outputs 2293568
Code:#include<stdio.h> void main() { int num[3]; /*Sets array to 10*/ int count; printf("Enter a 3 numbered integer:"); for(count=0; count<3; count++){ getchar(); } printf("%d", num); return; }
Last edited by Interista; 11-03-2011 at 11:24 AM.
I don't really know what you are trying to do, but here is an example based on your code:
Code:#include<stdio.h> int main(void) { int num[3]; int count; printf("Enter a 3 numbered integer:"); for (count = 0; count < 3; count++) { num[count] = getchar(); printf("%d\n", num[count]); } return 0; }
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
Code:#include<stdio.h> int main() { int num[3]; /*Sets array to 3*/ int count; char c; printf("Enter a 3 numbered integer:"); for(count=0; count<3; count++){ c=getchar(); printf("%c\n",c); } return 0; } ~
If you are trying to compile a 3 digit number like 192 using getchar()...
1) use scanf() it's just a whole lot easier.
2) you need this...
Code:num = 0; for (i = 0; i < 3; i++) { num = num *10; num = num + getchar(); }
