Thread: in need of a little explaination..

so i am given this code...

insert

Code:

#include <stdio.h>
 
void function1(int array[], int length);
 
int main() {
    int values[] = {2, 5, 1, 0, 3, 4};
    function1(values, 6);
    return 0;
}
 
void function1(int array[], int length) {
    
    int temp[length], i;
   
    for (i=0; i<length; i++) 
        temp[i] = array[array[i]];
       
    for (i=0; i<length; i++)
        array[i] = temp[i];     
    
    for (i=0; i<length; i++)
        printf("%d ", array[i]);
}

and i have to answer this question...

1) Let the array values be an integer array of size 6 storing the following values (in this order): 2, 5, 1, 0, 3, 4. What is the output of running the function call function1(values, 6)?

A) 2 5 1 0 3 4
B) 0 1 2 3 4 5
C) 5 4 3 2 1 0
D) 1 4 5 2 0 3
E)NOTA

The answer is D can anyone explain why? i just dont get it...

soooo
when i = 2, array[i] is 1. So array[array[2]]=array[1]=5?

thanks! it actually makes sense now