Getch Refresh? Simple Problems with Getch()

**justin777** · 10-25-2011

I use DevC++
and I have 2 problems

Code:

#include<stdio.h>
#include<conio.h>


main()
{
      int x = getch();
      
      printf("1st getch = %d",x);
      getch();
      printf("2nd getch = %d",x);
      getch(); 
      printf("3rd getch = %d",x);
      
}

First Problem: When I declare x = getch(); the getch there is not excluded, I mean you still need to put a value to go to the next statement. Is it possible skipping it in declaring for a variable?

Second Problem: The value of the my first getch() will be the value of all getch, I need a way to refresh it or delete the value of it.
For Example: I press Enter
Ascii Value of Enter is 13
Output would be:

1st Getch = 13
2nd Getch = 13 //I press other keys
3rd Getch = 13 //I press a different key

What I want is like
Output:

1st Getch = 13
2nd Getch = ## //The Ascii Value of another key
3rd Getch = ## // The Ascii Value of another key

Please Help

. I'm trying to solve this for 2 hours now, I tried fflush(stdin) but it wont work.

**quzah** · 10-25-2011

If you want to keep track of the key that getch is returning, you need to assign it to something. The line where you declare a variable doesn't magically make it refresh every time getch() is called.

Code:

int first, second, third;

first = getch();
second = getch();
third = getch();

Assigns three different return calls to the appropriate variables.

Quzah.

**justin777** · 10-26-2011

But Wait. If I did that the declaration of getch in the variables will not be excluded

Code:

#include<stdio.h>
#include<conio.h>


main()
{
      int x = getch(),y = getch(),z = getch();
      
      getch();
      printf("1st getch = %d",x);
      getch();
      printf("2nd getch = %d",y);
      getch(); 
      printf("3rd getch = %d",z);
      getch();
}

Here you will see I want is, before the printf It will ask the getch()
Before printf First Getch, that value of getch I want for my printf First Getch
Not the vualue in my declarations

**~~CommonTater~~** · 10-26-2011

Code:

#include<stdio.h>
#include<conio.h>


main()
{
      int x = getch();
      
      printf("1st getch = %d",x);
      x = getch();
      printf("2nd getch = %d",x);
      x = getch(); 
      printf("3rd getch = %d",x);
      
}

And you should be using getchar() not getch()

**justin777** · 10-26-2011

If I use getchar() I need to press Enter to execute it

Ok my project is like object oriented or a cheat way of having one

Like If I press left key the left box will have a border and if I press enter it will go to a function vice versa to the right

I use getch() because I don't need to press Enter when I input a key stroke

**~~CommonTater~~** · 10-26-2011

Ok... but you still need to capture the return value of the call *every single time*.

Code:

while (1)
  {   switch( getch() )
       {
           case '1' :
               printf("Function #1");
               break;
           case '2' :
               printf("Function #2");
               break;

           // and more cases as needed

           case 'Q' :
              printf("Bye Bye For Now!);
              exit(0);
          default :
              printf("Unrecognized entry"); } }

And... what you are writing is not even close to object oriented sillyness ... er, I mean "code"... what you are trying to emulate is a windows message queue... and in that case why not use the real deal?

http://www.winprog.org/tutorial/

**justin777** · 10-26-2011

Ok but How will I put it Arrow Keys?
Your solution is great but my problem now is arrow keys

**justin777** · 10-26-2011

Damn I got it, Thanks dude, I found a way. I convert it to be a int

New Problem

Arrow Keys give two values(I think) cause It activate Case 224 and Default

Both are showing up

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