Thread: I'm new taking my 1st class, and I am having trobble with my homework.. help please!

/*Homework2
Wednesday, September 21st, 2011 1:02 PM
Homework 2: The program asks user for a positve integer greater than 0 and less than 10. Program prints out:

1. whether number is even or odd
2. cube of number
3. square root of number
4. Sum of the digits
5. factorial

If an unsuitable number is entered, program exits only printing that an invalid number was entered.*/

Code:

#include <stdio.h>
#include <math.h> /* for sqrt*/


/* ask user to input a number between 1 and 10.
program will check number and terminate if input invalid
Otherwise the program will prnt out if the number is odd or even
value cubed, sqare root of the number, sum of the digits and factoral*/

int main()
{
    int number, i, sumx, productx, cubed, sqrt, factoral;
    printf(" enter a postive number between 1 and 10:");
    scanf("%d", &number);
    /* if ((number > 0 ) && (number < 11)).....*/
    
    { number/2 = even
    printf ("the number %d is even\n");
    else
    printf ("the number %d is odd\n"); /* 1 */ 
    }
    
    
    {cubed = (number*number*number)
    printf (" the number cubed is %d\n"); /*2*/
    }
    
    {sqrt = (sqrt(number))
    printf (" the number square root is %d\n"); /*3*/
    }
    
    {sumx=0;
    for (i=1;i<=number;i=i+1) 

    sumx =sumx+ i;
    printf("the sum of the digits is %d\n", sumx); /* 4 */
    
    for (i=1; i<= number; i=i+1)
    productx=productx*i;
    }
    
    {factoral=0;
    for (i=1;i<=number;i=i*1) 

    factoral =factoral* i;
    printf("factoral of this is %d\n", factoral); /* 5 */
    
    for (i=1; i<= number; i=i*1)
    factoral=factoral*i;
    }

  system("PAUSE");    
  return 0;
}

What is your question? Does the program work as expected or do you have some problem with it, if so what kind of problem?

it doesn't work... I can get only the sum of the numbers to work if I take all the rest out. I need the program to print 5 answers for each part of the assignment. the user enters if the user enters a number 1 though 10 then the program should print out answers to each of these questions...
1. whether number is even or odd
2. cube of number
3. square root of number
4. Sum of the digits
5. factorial

So lets say the user types in 2 I need it to output
2 is odd, the cube is 8 , square root is 1, sum of the digits is 3 and the factorial is 2

also dunno if this is a factor but I"m using dev C

Start by commenting out everything but the first part (odd/even), then add them in one after one until they are all working. Looking at the first part:

Code:

    /* if ((number > 0 ) && (number < 11)).....*/
    
    { number/2 = even
    printf ("the number %d is even\n");
    else
    printf ("the number %d is odd\n"); /* 1 */ 
    }

That is not even going to compile. The easiest way to determine if a number is uneven is to check if it's rightmost bit is set IMO.

what does it mean "it's rightmost bit is set IMO"? I don't think we learned that........

If you have not used bitwise operators then you haven't. But actually you could leave that bit since the first requirement (checking the range of the number) is commented out. So, solve that first. I would look for numbers < 0 and > 10 instead, if 'number' pass that test, print an error message and return 0; which will end the program.

I think I get what you mean... but I'm not sure how to do it correctly.... this is my attempt.....

Code:

int main()
{
    int number, i, sumx, productx, cubed, sqrt, factoral;
    printf(" enter a postive number between 1 and 10:");
    scanf("%d", &number);
    if (number > 0);
    printf (" number is not between 1 and 10\n");
    else
    if (number < 11);
    printf (" number is not between 1 and 10\n");
    
    /* if ((number > 0 ) && (number < 11)).....*/

thanks
-Cess

Originally Posted by Cess

I think I get what you mean... but I'm not sure how to do it correctly.... this is my attempt.....

Code:

int main()
{
    int number, i, sumx, productx, cubed, sqrt, factoral;
    printf(" enter a postive number between 1 and 10:");
    scanf("%d", &number);
    if (number > 0);
    printf (" number is not between 1 and 10\n");
    else
    if (number < 11);
    printf (" number is not between 1 and 10\n");
    
    /* if ((number > 0 ) && (number < 11)).....*/

thanks
-Cess

Code:

if ((number < 1) || (number > 10))
 { 
    printf("I specifically said from 1 to 10\n");
    exit(1); 
  }

  // rest of program here

If the number is less than 1 OR the number is greater than 10 the program exits.

Ok tried fixing it and still getting error.... We haven't used || before so I don't really know how to use it but ya this is what I did and got an error on the return line it says....

Code:

#include <iostream>
using namespace std;
int main()
    {
     int number;
     printf(" enter a positive number between 1 and 10:");
     if( (number < 1) || (number > 10) ) {
     printf("The number is out of range. (1-10)\n");
    
system("PAUSE");
return 0; }

You're going to get an error alright... you're using C++ headers and C doesn't have the first clue what "namespace" is.

Plus your brackets are mismatched ...