convert word to binary

**Supra** · 03-28-2002

How can I convert a word such as 'A' to the number represented in ASCII ? Another question is how can i convert a decimal number to binary number? Is any function in c allows us to do that?

Thanx for any help

**swoopy** · 03-28-2002

int num;
num = (int) 'A';

To convert a int to a binary string. One way is function itoa(), if your compiler has it.

Code:

#include <stdlib.h>
int main(void)
{
   int num = 255;
   char str[33];
   itoa(num,str,2);
}

And here's a clever function to print in binary that someone posted:

Code:

void printbits( int x )
{
   int y;
   for( y = 31; y >= 0; y-- ) printf("%d",(x&(1<<y))?1:0);
      printf("\n");
}

**usmadhav79** · 03-28-2002

will this also work?
int i;
i='A';
printf("%d",i)//prints ASCII value of 'A'

**Nutshell** · 03-28-2002

yes

**swoopy** · 03-28-2002

>will this also work?
Yes

**Supra** · 03-29-2002

big thanx for you guys!!
now another question is how can I mask those binary #
for ex:

111000101
if i want shift right to 3, it will become
101111000,
just like what shr does in assembly language, but how can i do that in c?
is any function allows us to do that?

**Magos** · 03-29-2002

X>>Y (Shifts X's bits Y steps to the right)
X<<Y (Shifts X's bits Y steps to the left)

**sean** · 03-29-2002

asm
{
DW BINARY NUMBER = "=x"
}

As long as you can find a way of replacing x with the number, that works...

**Supra** · 03-30-2002

really big thanks to you all!!
my last two questions are

1. how can i "and" or "or" those binary in c#?

ex:

Code:

            1100110
   (and)    0011100
----------------------
            0000100

2. how can i convert binary # back to decimal #?
or where can i find the tutorial web site about them?

Thanx again

**Shiro** · 03-30-2002

>1. how can i "and" or "or" those binary in c#?

Well in C:

& - binary AND
| - binary OR

I don't know about C#, but I guess it's the same as in C.

>2. how can i convert binary # back to decimal #?
>or where can i find the tutorial web site about them?

Binary number

bn ... b3 b2 b1 b0

Decimal

2^0 b0 + 2^1 b1 + 2^2 b2 + ... + 2^n bn

**klausi** · 03-30-2002

Not again!!!

Here´s my code; it´s my first real C-program:

Code:

#include <stdio.h>
#include <string.h>

#define PUFFER 256


void asctobin(void); /* converts ASCII-characters into binary digits */
void bintoasc(void); /* converts binary digits into ASCII characters */

unsigned char bin[]={1,2,4,8,16,32,64,128};

int main(void)
{
	char chose;

	for(chose=0;chose<40;chose++,printf("\n")) ; /* clear screen */

again:
	printf("Enter \'A\' to convert ASCII to binary or \'B\' to convert binary into ASCII: ");
	scanf("%c",&chose);
	if(chose=='A' || chose=='a') asctobin();
	else
	{
		if(chose=='B' || chose=='b') bintoasc();
		else{
			rewind(stdin); /* back to the begin of stdin; if more then one character was entered */
			goto again;
		} /* only accepts 'A','a','B' and 'b' as inputs */
	}

	return 0;
}


void asctobin(void)
{
        char string[MAX],c;
	int count,len;

	printf("Enter string (max length: 255 characters): ");
	rewind(stdin); /* back to the begin of stdin */
	fgets(string,PUFFER-1,stdin);

	len=strlen(string);

	for(;len>0;len--) /* as often as the value for the length of the inputed string */
	{
		c=*string; /* the character string points to at the moment */
		for(count=7;count>=0;count--)
		{        
			if(c>=bin[count])
			{
				printf("1");
				c-=bin[count];
			}else
			printf("0");
		}
		*string++;
		printf(" ");
	}
}


void bintoasc(void)
{
	char string[MAX],c;
	int count=7,len;


	printf("Enter digits (max 255):");
	rewind(stdin); /* back to the begin of stdin */
	fgets(string,PUFFER-1,stdin);

	len=strlen(string);

	for(;len>0;len--) /* as often as the value for the length of the inputed string */
	{
		if(*string=='1')
		{
			c+=bin[count], --count;
		}else 
		if(*string=='0') --count;

		if(count==0)
		{
			printf("%c",c);
			count=7;
			c=0;
		}

		*string++;
	}
}

klausi

**Supra** · 03-30-2002

thanx you all very much, but i still have questions about masking
number
I wrote a small program:

Code:

#include <stdlib.h>
int main(void)
{
   unsigned char i='a';
   unsigned char b='c';
   char str[33];
   i='a'+'c';
   printf("%d\n",i);
   itoa(i,str,2);
   printf("%s\n", str);
   i << 3;
   printf("%d\n",i);  //still can't shift
   i & 3;
   printf("%d\n",i); // still can't and
   return 0;
}

I can't mask the number
cna anyone tell me what's wrong with it?
really appreciate

Unregistered · 03-30-2002

Originally posted by Supra
i << 3;
i & 3;
I can't mask the number
cna anyone tell me what's wrong with it?
really appreciate

That is the same as typing this somewhere in your code:

1+6;

As you see, it does nothing. You have to store your result somewhere:

i=(i << 3); and i=(i & 3);

Or in an even simplier way:

i <<= 3; and i &= 3;

Good luck!

**Magos** · 03-31-2002

That was me replying above, for some reason you're not logged in if you enter this site from Hotmail.

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