Thread: send one part of struct array to function

  1. #1
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    send one part of struct array to function

    lets say i have this
    Code:
    typedef struct {int x}stru;
    void fun(stru *array){
     array->x=5;
    }
    int main()
    { 
     stru arra[5];
      fun(array[0])
    }
    the problem is that i want to send only one place of the array not all of it
    can you tell me whats the wrong code?

  2. #2
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    You don't return an int from main like you're supposed to. You also have a typo, you declare it as arra, but pass it as array. Also, your function expects a stru *, but you pass array[0] which is just a stru. You either need to change the funciton definition to take a stru, or change the function call to pass the address of array[0].

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    hello
    how can i change the function call to send the arra position 4 for example
    i need to leave function declare as it is

  4. #4
    and the hat of int overfl Salem's Avatar
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    fun(&array[4])
    ought to do it.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

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    Registered User sagar474's Avatar
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    why don't you just pass a pointer to the structure. ?
    what do you mean that "one place"? do you mean that only one struct in a array of structs?

  6. #6
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    Quote Originally Posted by cable View Post
    hello
    how can i change the function call to send the arra position 4 for example
    i need to leave function declare as it is
    Code:
    fun(&arry[3]);
    You really should pop open your textbooks and re-read the sections on arrays and pointers.

  7. #7
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    Quote Originally Posted by Salem View Post
    fun(&array[4])
    ought to do it.
    Ummm... isn't that position 5?

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    guys please give me an code example for the next question
    Code:
    typedef struct {int x}stru;
    void fun(stru *array){
     array->x=5;
    }
    int main()
    { 
     stru arra[5];
      fun(&arra[4])
    return 0;
    }
    what change i need to do for this
    Code:
    fun(&arra[4])
    (which is not working) to make it send the fifth struct of the array of struct arra
    edit: or if you know a better way write it to me (always without changing the function declare)

  9. #9
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    Ok we're not about to babysit you through replacing a 4 with a 5...

    Really... turn that big brain of yours back on...

    You need to read up on loops and arrays...
    You can start.... here

    And it's not working because your struct definition is wrong...
    Code:
    typedef struct {int x}stru;
    
    // should be
    
    typedef struct t_stru
      { int x;
       } stru;
    If you would set your code up properly you would have spotted that on your own.
    Last edited by CommonTater; 09-22-2011 at 12:51 PM.

  10. #10
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    edit:
    anyone else? about my question
    Last edited by cable; 09-22-2011 at 12:44 PM.

  11. #11
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    Quote Originally Posted by cable View Post
    edit:
    anyone else? about my question
    Quote Originally Posted by cable View Post
    guys please give me an code example for the next question
    We're not going to hand you a code sample. We actually have a policy about this. 10 months and 30 posts on this board, you should know that by know. You should also know we expect some effort from you towards solving your problems. We've told you what you need to know and where to read up on it. You have to put in a little effort yourself. Note, arrays in C start at 0 and go to size-1, so your array only has array[0] to array[4]. There is no array[5].

    what change i need to do for this
    Code:
    fun(&arra[4])
    (which is not working) to make it send the fifth struct of the array of struct arra
    What's not working about it? You need to be specific. It looks like it's correctly sending the 5th element to me.

  12. #12
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    edit:
    anyone else? about my question

    Don't you just love it when they completely blow you off like that?

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