Hi guys, I'm new and I got problems :)

[linx2001]

C problems that is ^.^
My name is Allen and it's my first time posting a thread here and I figure I'll introduce myself along with a problem I'm having. I'm new to C programming so I'm doing an assignment and the logic seems ok to me but for some reason when I enter lets say 50.99, the while loop won't work right. Here's my code

printf("What is the cost of small package(s) (in dollars, 0< cost < 500): ");
scanf("%e", &s_pack);  //Storing the user's input
//Using while loop to make sure the input is valid
while (s_pack > 500 || s_pack < 0) {
printf("The amount you have entered is not within the parameter.\n");
printf("Please enter the cost of small package(s) in dollars between 0 and 500: ");
scanf("%e", &s_pack);
}

I entered 50.99 which is obviously false in the while loop but the loop ran anyway. I'm pretty sure I did something stupid but I dont know what. I will appreciate it if anyone can help ^.^

[Adak]

Add a printf() line of code as the very first line of your while loop, and see what value s_pack has.

That would be basic debugging, and show you the problem.

while (s_pack > 500 || s_pack < 0) {
printf("The value of s_pack is: %*\n", s_pack);

printf("The amount you have entered is not within the parameter.\n");
printf("Please enter the cost of small package(s) in dollars between 0 and 500: ");
scanf("%e", &s_pack);
}

*Replace with either f for float or lf for double data type - or use the proper format for s_pack.

[linx2001]

Oh wow! All I did was changed %e to %lf and it worked! Thanks so much! ^.^ I wonder why though o.o I read over c programming and %e should also work.

[TheBigH]

That's because %e is for floats and %lf is for doubles. They are different data types.

[CommonTater]

C problems that is ^.^
My name is Allen and it's my first time posting a thread here and I figure I'll introduce myself along with a problem I'm having. I'm new to C programming so I'm doing an assignment and the logic seems ok to me but for some reason when I enter lets say 50.99, the while loop won't work right. Here's my code

printf("What is the cost of small package(s) (in dollars, 0< cost < 500): ");
scanf("%e", &s_pack);  //Storing the user's input
//Using while loop to make sure the input is valid
while (s_pack > 500 || s_pack < 0) {
printf("The amount you have entered is not within the parameter.\n");
printf("Please enter the cost of small package(s) in dollars between 0 and 500: ");
scanf("%e", &s_pack);
}

I entered 50.99 which is obviously false in the while loop but the loop ran anyway. I'm pretty sure I did something stupid but I dont know what. I will appreciate it if anyone can help ^.^

A little hint for next time... when posting code snippets you shoule also show us the declarations of any variables you are referenceing...

[iMalc]

That would be basic debugging, and show you the problem.

That would be slightly condescending. You get that here from time to time.
But luckily such things are overlooked when the associated advice does the trick anyway.

[Adak]

It's suggestive of a basic debugging method that I would use. It's described as a basic technique, because adding a print statement, is a basic debugging technique.

At no time does it suggest the OP is somehow less intelligent than anyone else, and is certainly *not* condescending. I do get a bit sharp with the OP's that are showing very little effort, but this wasn't the case here.

[linx2001]

Thank you all for your suggestions and tips, probably somewhere in my head, I read the data type wrong and thought %e for double. I learned my mistakes and will improve to become better