multi string arrays

[nasser]

Hi

If I have:

	char bit_pattern[][4][4] = {
		"0000", "0001", "0010", "0011",
		"0100", "0101", "0110", "0111",
		"1000", "1001", "1010", "1011",
		"1100", "1101", "1110", "1111"};

How do I extract an element/string i.e "0000", "0001" etc

Thanks

[manasij7479]

How do I extract an element/string

By the first two 'coordinates'.

[nasser]

I tried that, when I do:

printf("\n\nbit_pattern: %s\n\n", bit_pattern[1][1]);

I get: bit_pattern: 01010110011110001001101010111100110111101111, which is basically some combination of the elements.

[CommonTater]

Hi

If I have:

	char bit_pattern[][4][4] = {
		"0000", "0001", "0010", "0011",
		"0100", "0101", "0110", "0111",
		"1000", "1001", "1010", "1011",
		"1100", "1101", "1110", "1111"};

How do I extract an element/string i.e "0000", "0001" etc

Thanks

As manasij points out ...

printf("%s", bit_pattern[i][j]);

where i and j are the first two indexes of your array.

[CommonTater]

I tried that, when I do:

printf("\n\nbit_pattern: %s\n\n", bit_pattern[1][1]);

I get: bit_pattern: 01010110011110001001101010111100110111101111, which is basically some combination of the elements.

Depending on your compiler, you may need to change your intializer...

	char bit_pattern[4][4][] = {
		"0000", "0001", "0010", "0011",
		"0100", "0101", "0110", "0111",
		"1000", "1001", "1010", "1011",
		"1100", "1101", "1110", "1111"};

or

	char bit_pattern[4][4][] = {
		{"0000", "0001", "0010", "0011"},
		{"0100", "0101", "0110", "0111"},
		{"1000", "1001", "1010", "1011"},
		{"1100", "1101", "1110", "1111"}
                         };

[jimblumberg]

Shouldn't

char bit_pattern[4][4][]

be

char bit_pattern[][4][5]

or

char bit_pattern[4][4][5]

Jim

[AndrewHunter]

I tried that, when I do:

printf("\n\nbit_pattern: %s\n\n", bit_pattern[1][1]);

I get: bit_pattern: 01010110011110001001101010111100110111101111, which is basically some combination of the elements.

Try something like:

#include <stdio.h>

int main(void){

	char myarray[][4][5]={{"0000","0001","0010","0011"},
	{"0100","0101","0110","0111"},
	{"1000","1001","1010","1100"},
	{"1101","1110","1111","0000"}};

	for(int x=0;x<4;x++)
		for(int y=0;y<4;y++)
			printf("%s\n",myarray[x][y]);

	getchar();
	return(0);
}

[CommonTater]

Shouldn't

char bit_pattern[4][4][]

be

char bit_pattern[][4][5]

or

char bit_pattern[4][4][5]

Jim

This is something that, from experimenting with different compilers, I interpret as "implementation dependent"... while the last one is almost certainly correct... the others may not be. (In my experience... not per any known standard.)

[nasser]

AndrewHunters suggestion worked, thanks.

[nasser]

One more question, how can I assign a pointers value into an array i.e

where printArray is a pointer to a char got from a function. This doesn't seem to work:

for(i=0; i<10;i++) {

empty[i] =  *(printArray+i);

}

But I can print the individual characters of *(printArray + i) and get the right characters just fine. thanks

[iMalc]

Clearly this is for that hex to binary conversion again, in which case the dimensionality of the array should be reduced by one. Make it char bit_pattern[16][5]