Thread: Syntax for functions

First since board has been defined as int board[MAX][MAX] your function signature should have board with the same size, not the user entered size.

Second when you call the function you are calling like: printBoard(size, align, board[MAX][MAX]); The third argument should be a int board[MAX][MAX] but your call is sending a single int which also happens to be out of range for your array.

So your code should look like:

Code:

#define MAX 100

void printBoard(int size, int align, int board[MAX][MAX]);

int main(int argc, char *argv[]) {
    int board[MAX][MAX] = {{}}; // intialized elements to zero
    int size = 0;
    int align = 0;
    
   printBoard(size, align, board);

   return 0;
}

void printBoard(int size, int align, int board[MAX][MAX]) {
    int i,j;

    for (i=0; i<size; i++) {
        for (j=0; j<size; j++) {
            printf("%*d", align, board[i][j]);
        }
    }
}

You may want to look at this link for a refresher on arrays. Pay particular attention to the section titled: "Arrays as parameters".

In future posts please post the complete error message exactly as they appear in your development environment. These messages have important information embedded in them to aid in the discovery of the location and probable cause of the problem.

Jim

Oh thanks for all the help!

I had no clue arrays were passed into functions without the brackets, and the link says that when I create a function, the array needs to be expressed as such:

base_type[][depth][depth]

So since I don't determine the value of size till later on in my code, I should leave the function as board[][MAX] and then pass int size into the functions as well, then I'll shorten my array to board[size][size] from there. That's what it seems like you've done.

I would've posted the full error message if I didn't cut out most of my code, because the line number is useless in this case. Should I just post my full code and the complete error reports in future?