I'm Using break; on every case, but whenever i type in any number,Code:#include <stdio.h> int main() { //Hold Numeric Char entered by user char c; //holds boolean value for Done int done; //Holds the value of the total price float total = 0; //Prompt printf("Hello, please enter your selection: \n"); printf("1 - Candy\n"); printf("2 - Beverage\n"); printf("3 - Hotdog\n"); printf("4 - Popcorn\n"); printf("0 - Done\n"); printf("Your Choices: \n"); //Variable done Initialized to 0(False) done = 0; //Get and Handle Input while(!done) { //Get Input c = getchar(); switch(c) { case '1': printf("Candy\t$3.00\n"); total+=3; break; case '2': printf("Beverage\t$5.50\n"); total+=5.5; break; case '3': printf("Hotdog\t$10.00\n"); total+=10; break; case '4': printf("Popcorn\t$4.99\n"); total+=4.99; break; case '0': printf("Total: $%.2f\n", total); printf("Please Pay at the Cashier, Thank You."); done = 1; break; default: printf("Improper Selection!"); break; } } getchar(); return 0; }
default is always executed despite the break statements...
Why is that? :S