Thread: Converiting a flowchart into code

I found this flowchart on the internet and was wondering what would be the most efficient way to program this on C.

I was thinking along the lines of either switch, do-while, or if-else functions but what's the best way and could someone give me a sample I can go by just to start me off? I'm also curious about how you're supposed to make the program loop at a certain point (i.e. The Begging part) until it gets a yes.



-Thanks in advanced

Originally Posted by Defgrav

I found this flowchart on the internet and was wondering what would be the most efficient way to program this on C.

For starters convert pictures into pseudocode, then code it in C.

Originally Posted by Defgrav

...I'm also curious about how you're supposed to make the program loop at a certain point (i.e. The Begging part) until it gets a yes.

In that case pickup a good book on C and read it cover-to-cover.
There are plenty of good books suggested in the sticky on this site.

Thanks to all who replied, I did go through a bit of the stickies and the C tutorials and I coincidentally did what Adak said exactly . I divided it into a YES and NO branch and encased it all in a do-while loop to allow repetition if i !=0 . I dunno if it'll work though, but from what I read the program reads it line per line so i think the order of the If-else's is right but then again I'm new to this so any constructive criticism is welcome and well appreciated !

Here's my pseudo-code,
P.S. To all nazi-coders out there please forgive me >.<

Code:

/* Include libraries and declarations of variables and other pre-processor directives */
      
      
/*Process starts off from here*/      
      printf("Can I eat it?: ");
      scanf("%c", &answer);

switch (answer)   /* a switch to seperate the inital YES and NO branches-*/
       {          /*- which will be cut short to accomodate the YES and NO branch connections */
       case '1':    /* will be the YES branch */
         printf("Eat it");  /* this part is separated because in the flowchart the NO branch connects with the YES branch and will loop AFTER the EAT IT statement */
         do {      /* something to make the program loop from the beggining given a certain condition*/
            printf("...Did it taste good?: ");
            scanf("%c", &answer);
/* 1 */     if(char answer = yes ){
                printf("\nAm I still hungry?: ");
                scanf("%c", &answer1);
                }
/* 2 */         if(char answer1 = yes){
                        printf("\nIs there anymore?: ");
                        scanf("%c", &answer2);
                        }
/* 3 */                 if(char answer2 = yes){
                                printf("\nCan I get it without begging?: ");
                                scanf("%c", &answer3);
/* 4 */                         if(char answer3 = yes){
                                        i++;
                                        }
                        }
/* 1 */                         else if(char answer = no){
                                     printf("\nStop eating...Take a nap.);
                                     exit;
                             }
/* 2 */                 else if(char answer1 = no){
                              printf("\nYes I am!);
                              i++;
                              }
/* 3 */          else if(char answer2 = no){
                      printf("\nTake a nap.");
                       exit;
                        }
/* 4 */      else if(char answer3 = no){
/* B */           do{
                     printf("\nBEG...Did he/she give it to me?: ");
                     scanf("%c", &answer4);
                  }
/* 4.1 */         if(answer4 = yes){
                       i++;      /* allows the program to exit do-while loop B and enter into do-while loop A and since here i = 1 the condition of do-while loop A-*/
                       }         /*- will make it repeat from the beginning of do-while loop A which is what we want */
/* 4.1 */         else if(char answer4 = no){
                        i--;    /* if this condition is fullfilled it will repeat do-while loop B until it a YES is given in which case it exits the loop.*/ 
                        }
/* B */           }while(i != 1) /* this do while loop will only occur if the condition of the 4th else-if before it is fulfilled and will loop so long as i is not(!)-*/
                                 /*-equal to 1 ( i is always initially 0 )*/
       
       case '2'  /*Will serve as the NO branch*/
            printf("\nIs it safe to try eating?: ");
            scanf("%c", &answer);
/* 5 */     if(char answer = yes){
                printf("Eat it");   /* because we separated the first EAT IT statement because I have no idea how to make it skip a part rather I'll just resort to inserting which is easier*/
                i++; /* This will evidently make the program loop back INTO the YES branch seeing as there is a connection */
            }
/* 5 */     else if(char answer = no){
                 printf("\nShould I try eating it anyway?");
                 scanf("%c", &answer);
                 }
/* 6 */          if(char answer = yes){
                         printf("\nEat it...Am I still okay?: ");
                         scanf("%c", &answer);
                         }
/* 7 */                  if(char answer = yes){
                                 i++;
                         }
/* 6 */                  else if(char answer = no){
                              printf("Take a nap.");
                         }
/* 7 */           else if(char answer = no){
                         printf("RUN TO KHOI.");
                  }
}while (i != 0);   /* when i is not(!) equal to 0 the do while will keep repeating*/
/* take note that from here i MUST be equal to 0 or else it would have repeated do-while loop A*/
      
      return 0;  /* they said it's always good to return to main, also a force of habit thanks to my professors */
}

@quzah Oh I thought switches could be used for even just 2 cases, oh wait do you mean it naturally has 2 cases and that default thing it mentioned is the 3rd one ? Or is it really just impractical to use a switch for 2 cases only ?

@Adak

Thanks! It was a little sloppy since I started late and ended at 1 am haha, I even missed a label or two and I'm not even sure if all the brackets are balanced. But good to know it's a viable code .
Oh and thanks a lot for the corrections on my condition part and my scanf's, I would never have figured those out if I actually tested O.O

I like the way you've numbered the logic out, in the program. I'd prefer you used more functions to make the code more readable and easier to write, but I know using functions is perhaps more difficult for you, just now.

May I ask what functions your referring to? Just out of curiosity

This is what I meant by using functions, in your code. This code has not been tested, btw.

Code:

#include <stdio.h>
#include <stdlib.h>

void beg(void);
void eatIt(int);
char isSafeToTry(void);
void stopEating(void);
void takeNap(void);

int main () {
  int no2yes=0, cry=0;
   char answer;
   printf("\nCan I Eat It? [y/n] ");
   scanf("%c", &answer); getchar();
   if(answer=='y') {
      no2yes=0;
      eatIt(no2yes);
   }else {
      answer = isSafeToTry();

      if(answer=='y')
         eatIt(no2yes);
      printf("\nShould I eat it anyway? [y/n] ");
      scanf("%c", &answer); getchar();

      if(answer=='n') 
         takeNap();
      printf("I'll try eating it!\n");
      printf("\nAm I still OK? [y/n] ");
      scanf("%c", &answer); getchar();

      if(answer=='y') {
         no2yes=1;
         eatIt(no2yes);
      }else {
         printf("\nRun crying to Mom!\n");
         cry=1;
      }
   }

   if(!cry)
      takeNap();
	return 0;
}
void beg(void) {
   char begAnswer='n';
   while(begAnswer=='n') {
      printf("\nPlease can I have some?, I'm hungry! [y/n]");
      scanf("%c", &begAnswer); getchar();
   }
}
void eatIt(int no2yes) {
   char answer; 
   int begWorked = 0;
   if(no2yes==0)
      printf("\nEat It.\n");
   printf("\nDid it taste good [y/n]?");
   scanf("%c", &answer); getchar();
   if(answer=='y') {
      answer='n';
      while(answer!='y') {
         printf("\nAm I still hungry [y/n]?");
         scanf("%c", &answer); getchar();
         if(answer == 'y') printf("Yes I am!\n");     
      }
      if(answer=='y') {
         printf("\nIs there any more [y/n]?");
         scanf("%c", &answer); getchar();
         if(answer=='y') {
            printf("\nCan I get it without begging? [y/n]:");
            scanf("%c", &answer); getchar();
            while(answer=='n') {
               beg();
               printf("Did he/she give it to me? [y/n]: ");
               scanf("%c", &answer); getchar();
               begWorked = 1;
            }
            if(!begWorked) {
              printf("Did he/she give it to me? [y/n]: ");
              scanf("%c", &answer); getchar();
              begWorked = 0;
            }
            eatIt(no2yes);
         }else 
            takeNap();
      }
   }else {
      stopEating();
      takeNap();
   
   }
}
char isSafeToTry(void) {
   char answer;
   printf("\nIs it safe to try eating it? [y/n] ");
   scanf("%c", &answer); getchar();
   return answer;
}
void stopEating(void) {
   printf("\nStop eating\n");
}
void takeNap(void) {
   printf("\nTime to take a nap, goodbye. \n");
   exit(0);
}

I'm not good at working from flowcharts. We used pseudo code in my class.