Having a problem with a Switch Statement

**ARod609** · 07-13-2011

Originally Posted by quzah

Code:

if ... will always run this if check
if ... will always run this check
else
    will only run if that was not true

Compare that with this:

Code:

if ... always runs this if check
else if ... only after the first test was false
else ... when neither was true...

.

So that could cause a conflict in more complicated programs?

**quzah** · 07-13-2011

Originally Posted by ARod609

So that could cause a conflict in more complicated programs?

You have to think about what you want your program to do. Watch:

Code:

if( x == 1 )
    printf( "x is one\n" );
else
if( x == 2 )
    printf( "x is two\n" );
else
    printf( "x is not one or two\n" );

Compared to what you have:

Code:

if( x == 1 )
    printf( "x is one\n" );
if( x == 2 )
    printf( "x is two\n" );
else
    printf( "x is not one or two\n" );

What is the output of this if x is 1? Is that what you wanted the program to do? You need to think through what you want to do.

Quzah.

**ARod609** · 07-13-2011

Output

Code:

x is one
x is not one or two

I see, so the first "if" function and the "else" perform there functions because the code did not clarify what process it wanted to follow?

Thread: Having a problem with a Switch Statement