Thread: Problem with I/O program

No Tater, I think you're misunderstanding. He's passing a 2-d array to the function, which is demoted to a pointer to an array of 21 chars. He could also have written char textArray[][21]. Just like you can do char *foo or char foo[] for a 1-d array.

Originally Posted by anduril462

No Tater, I think you're misunderstanding. He's passing a 2-d array to the function, which is demoted to a pointer to an array of 21 chars. He could also have written char textArray[][21]. Just like you can do char *foo or char foo[] for a 1-d array.

OOPS... my bad. Sorry... I don't think I've ever seen it written like that before.

Code:

             else if(in_word ==1)
             {
                   textArray[i][j] = '\0';
                   i++;
                   j = 0;
                   in_word = 0;
             }
    }
    first_word_total = i;   
  
    
    for(i = 0; i < first_word_total; i++)
    {
          for(j = 0; j != '\0'; j++)
          { 
             textArray[i][j] = wordArray[i][j];
          }
    }
    
    for(i = 0; i < first_word_total; i++)
    {
          for(j = 0; j != '\0'; j++)
          {
                printf("%s\n", wordArray[i]);
          }
    }
    
    //return word_total;

I went back a put a null character at the end of the line, indicating the end of the string. Now when I run the program, it doesn't seem to copy anything, and only prints a blank list... It doesn't compare anything yet, but I'll get to that after I get the arrays to copy successfully. The bold part of the code is just to display the contents of wordArray, for debug purposes. So far nothing yet.

I've tried single and double for loops so far, but to no avail...

I'll try strcpy since there is now '\0' at the end of each line and see where that gets me.