Thread: what will be the output and plz explain me

Code:

#include<stdio.h>
void main()
{
  int i=-1,m;
  m=i++;
  printf("%d %d",i,m);
}

The output will be 0 and -1...

This is because of the m = i++ line... m is assigned the value of I (-1) and then I is incremented to 0.

FWIW... the correct form of main is... int main (void) ... and C programs always return a value to the operating system on exit...

Code:

#include<stdio.h>

int main (void)
  {
    int i=-1,m;
    m = i++;
    printf("%d %d",i,m);

  return 0;
}

Originally Posted by ssharish2005

>What will be the output ehh?
Why couldn't you try compiler it to youself and see? Was it that hard to do it?

ssharish

It's probably a fair guess that he has done just that but didn't understand the answer he got...

Originally Posted by ssharish2005

But he never put it that way did he? He asked whats the output. Perhaps he could have been much smarter in asking questions.

ssharish

Yes he could have... but the question was sincere, he wanted to know what was going on...
I see no problem with giving him an answer.

I see no problem with giving him an answer.

I second this. I am assuming the poster is relatively new to programming, and the pre/post increment operator can lead to confusing problems if you don't understand the subtle difference between them.