argv, taking random char input

[astral]

Hi, how can you pass any char as an argument to a program e.g. $ and simply place it as a char, not a variable.

int main(int argc,char *argv[]) {
...

Here is an example:

./a.out "x3i0$fe$nk$l1o82wa2#kr0pd5#44le9$g553mf7"

fe: Undefined variable.

See the problem, it's taking the $fe, as a variable (when it's supposed to simply put each $ f e into my char array), and who knows what other problems could occur, since this is a a massive 700char random string (which I simply trimmed to show as an example to you). How can I input any CHAR as an argument, it must be valid for all common ASCII char 0-127.

[tabstop]

I don't have any idea what your question is. For that command line, argv[1] would be "x3i0$fe$nk$llo82wa2#kr0pd5#44le9$g553mf7". What you do with it is up to you.

[laserlight]

Try using single quotes to quote the command line argument.

[astral]

Try using single quotes to quote the command line argument.

Such a simple solution, how did I miss that. Cheers.

[ssharish2005]

Strangely enough, I’m able to read the command lines with no double quotes, no single quotes, with single quotes and double quotes.

ssharish