Code:#include <stdio.h> #include <string.h> #define MAX 4 int main(){ char str[2][MAX] ={"mom", "dog"}; char *pch; char *pch1; *pch = str[0][1]; *pch1 = pch+MAX; printf("%c, %p", pch1, pch1); return 0; }
Hi, I want to be able to compare if the middle letters are the same. This is just a snippet. I wanna see if I can add the MAX (4) including the '/O' character to the pointer to get into the next string.
You know what I mean?
:P
That is correct -- adding the size of the second dimension to a pointer will move you "down" a column in your array.
I don't understand - the value of the middle letters won't affect where the next string is located. The length of the string will.
edit: Nevermind, I see what you are asking.
Several issues. You should not assign the letter 'o' (or any value) to what pch points to when that pointer was not initialized. Same goes for pch1.
I think what you meant was:Note carefully the absense of '*' in the pointer assignments, the use of '&', and the inclusion of '*' when you wish to display the character.Code:pch = &str[0][1]; pch1 = pch + MAX; printf("%c, %p", *pch1, pch1);
Last edited by nonoob; 06-10-2011 at 08:24 AM.
Good catch -- you want to assign the value of pch, not the value of *pch.
I also wanted to add:
Because your array is 4 wide, yes you can add 4 to get to the same place in the next row. It has nothing to do with terminating '\0' in the strings.
I think what he was trying to say was that all the text was 3 chars long, so 3 + the NULL would be 4.Originally Posted by nonoob
Ah thank you. I kept ending up getting S
And I was wondering why I was only adding 4 to the ASCII numbers.
Thank you again.
I get confused when to put the *.
Right, but that's not why it works -- it works because the second dimension of the array is 4, regardless of what's actually in the array itself.
