Thread: Array size problem in C

Is it possible to declare an array without specifying the size of the array ?
I tried this

Code:

int i[];

also tried this

Code:

int i[]={};

but none of this seems to work..... Pls help me......

Thanks Salem.
Can you pls explain your code

Code:

void foo ( char array[] );

Use pointer declaration and dynamic memory allocation

Code:

int *i;
// ...
i = malloc(number_of_elements * sizeof(int));
// ...
free(i);

No and yes...

Code:

int i[] = {1, 2, 3, 4, 5}

If the array values are unknown you'll have to allocate space for the array later, when you know how much space is needed.

Code:

int *i;

[...]

i = malloc(sizeof(int) * array_len);

You can't append or push values onto the array with the standard libraries. However, there are libraries that emulates that behavior.

Code:

void foo ( char array[] );

The function foo accepts an array of characters, which actually degrades to a char *. If you looked at this in the debugger you would see it is being treated as

Code:

void foo ( char *array );

Originally Posted by Salem

> Thanks Salem.
> Can you pls explain your code
Read your book / course notes / tutorials.

I thought you might be kind enough to share your knowledge but am obviously wrong..... Sorry for asking you to explain

It is your responsibility to learn things. It is your school/tutor to teach you these things.
If they don't, you have to ask them.
Even if you are not student, you could still read online tutorial or books.
Forum is not a place to teach you basic C programming skill, we are here to help you solve your problem.
The fundamental thing like this should be covered by yourself using your own effort.
Why don't you see recommended books and read them up.
If you don't understand, come here back and ask what you don't understand.