Thread: opendir fail

open dir return null and i don't now why .

the code is :

Code:

int main(){

char buff[1000]; 

strcpy(buff,"."); 

lsFunc(buff); 


}


void lsFunc(char* toSend){
  
  void* myDir;
  struct dirent* ent; 


  
  if(!strcmp(toSend,""))  myDir=opendir(".");
  else			 myDir=opendir("toSend"); 

perror(NULL); 
printf("%d\n",errno);
}

and the output is :
"No such file or directory
2
Segmentation fault"

Thank you for your help
eyal

Code:

  if(!strcmp(toSend,""))  myDir=opendir(".");
  else			 myDir=opendir("toSend"); 

perror(NULL);

The quotes are wrong. Let's assume if is true, then you open dot, but if it's false, you open "toSend" literally, not the value of toSend, whatever it is.

perror (NULL); always executes and is likely to seg-fault since perror will access the pointer to print that value to stderr, and accesses to NULL are undefined behavior.

i am idiot .
thank you !!