alter the result in the end

[narendrav]

i use codeblocks for compiling.The following is the code that I have written.

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int n;
    printf("enter the number\n\n");
    scanf("%d",&n);
    printf("\n\n%d\n",n);
    while(n>0)
         {

             printf("%d\n",n/10);
             n=n/10;

         }

    return 0;
}

if 1234 is entered then it produces the following result

1234
123
12
1
0

now i want to have only upto 1 and eliminate o.I am not able to do this can anyone help me.

[CommonTater]

Yep.... divide before display and remove the /10 from the display line.

[narendrav]

i have changed it like this.

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int n;
    printf("enter the number\n\n");
    scanf("%d",&n);
    printf("\n\n%d\n",n);
    while(n>0)
         {
             n=n/10;/**changed here**/
             printf("%d\n",n);/**changed here**/



         }

    return 0;
}

But it still shows the same result

[CommonTater]

i have changed it like this.

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int n;
    printf("enter the number\n\n");
    scanf("%d",&n);
    printf("\n\n%d\n",n);
    while(n>0)
         {
             n=n/10;/**changed here**/
             printf("%d\n",n);/**changed here**/



         }

    return 0;
}

But it still shows the same result

Ok... so now modify the exit condition of your loop...

Two things to try...
first ... less than what?
second ... switch the loop around to a do..while() loop and see what happens.

One of the really fun things about programming is *experimenting* and seeing the results. Seriously, it's the absolute best way to learn.

[anduril462]

Ditch the printf before the loop and use a do-while. Inside the loop, print the undivided number then divide.