How to get a value Before/After a decimal point in C ??
Hi,
I'm new to C, I would like to achieve the following.
get two numbers after the decimal point
23.456 -> 0.45
11.235224 -> 0.23
and get all the numbers before the decimal point
23.456 -> 23
11.23 -> 11
.42 -> 0
How can I do it? I know it might be easy to some, but for me I still don't feel comforatble with C.
Last edited by ammar555; 05-18-2011 at 12:55 PM.
23.456 is a floating point number
Thats simply an integer version of your floating point number.23.456 -> 23
.456 is what's left if you subtract your integer from your float. You might have to play around with your code to get it to work right if you don't fully understand how c handles integers and floats.
Here is my code, but it doesn't quit work.
Code:int main() { float cost; //Define the cost as float float paid; //Define payments as float float sum; printf("Total Cost: "); scanf ("%f", &cost); printf("Paid: "); scanf("%f", &paid ) ; sum = paid - cost; //Subtract payments from the cost printf ("\n%.d dollars", sum); }
You can use the trunc function in math.h to get the integer portion, then subtract that from the float to get the decimal portion. Depending on your setup, you may need to link the math library separately.
Read up on how to use printf. You don't get to mix and match format specifies all willy-nilly. %d is for printing an integer (meaning sum is of type int, not "I want to drop the fractional part").Code:int main() float sum; ... printf ("\n%.d dollars", sum);
I'm trying to make a program that calculates the change , like below.
Total Cost: 2.23
Paid: 3.00
Results: $.77
3 quarters
0 dimes
0 nickels
2 pennies
Let's say now we entered the following .
Total Cost: 3.25
Paid: 10.00
Result: $6.75
27 quarters (I don't want it all to be in quarters, I need dollars too.)
0 dimes
0 nickels
0 pennies
so I was trying to take the value before the decimal point and count it as dollars and what's after I will count it in quarters, dimes or whatever as needed.
Last edited by ammar555; 05-18-2011 at 01:22 PM.
Here is my code
Code:#include <stdio.h> #include <stdlib.h> const int QUARTER = 25; const int DIME = 10; const int NICKEL = 5; const int DOLLAR = 100; int main() { float cost; //Define the cost as float float paid; //Define payments as float char ch; float sum; int sum2; int amount, dollars, quarters, dimes, nickels, pennies; printf("Total Cost: "); scanf ("%f", &cost); printf("Paid: "); scanf("%f", &paid ) ; sum = paid - cost; //Subtract payments from the cost //printf ("\n%.f dollars", sum); printf ("\n\n-------------"); printf ("\n%.2f Result", sum); printf ("\n-------------"); amount = sum * 100; quarters = amount / QUARTER; amount = amount % QUARTER; dimes = amount / DIME; amount = amount % DIME; nickels = amount / NICKEL; pennies = amount % NICKEL ; printf("\n\n%d quarters\n%d dimes\n%d nickels\n%d pennies\n", quarters, dimes, nickels, pennies); printf("\n\nContinue? (y/n)"); while(kbhit()) getch(); /* clear the input buffer */ do ch = getch(); while(ch!='y' && ch!='n'); while(ch=='y'); return 0; }
Originally Posted by mike65535
I found it thanks, here is my code for those who will need it in the future.
Code:int main() { float cost; //Define the cost as float float paid; //Define payments as float int sum; float sum2; printf("Total Cost: "); scanf ("%f", &cost); printf("Paid: "); scanf("%f", &paid ) ; sum = paid - cost; //Subtract payments from the cost printf ("\n%d dollars", sum); sum2 = (paid - cost ) - sum; printf ("\n%.2f Remainder", sum2); //sum2 = sum - (paid - cost); //printf ("\n%d dollars", sum); return (0); }
Last edited by ammar555; 05-18-2011 at 01:50 PM.
