Thread: decimal to binary conversion

Hello,

I saw it.
I have now this

Code:

/*
 *  * =====================================================================================
 *   
 *          Filename:  test2.c
 *    
 *          Description:  conventer from dec to 0101
 *       
 *          Version:  1.0
 *          Created:  14-05-11 10:03:25
 *          Revision:  none
 *          Compiler:  gcc
 *            
 *          Author:  Dr. Fritz Mehner (mn), [email protected]
 *          Company:  FH Südwestfalen, Iserlohn
 *               
 * =====================================================================================
  */

#include        <stdio.h>
#include        <stdlib.h>

int
main ( int argc, char *argv[] )
        {
            int nummer, uitkomst, teller, teller2;
            char uitkomst2[10];
            nummer = 4 ;
            uitkomst = 4 ;
            teller = 0 ;
            while (uitkomst > 0)
                {
                        uitkomst = nummer / 2 ;
                        uitkomst2[teller++]= uitkomst%2;
                        nummer = uitkomst;
                        printf ("teller:%d  deling:%d uitkomst deling:%d  \n",teller, uitkomst%2, uitkomst);
                }
            teller2 = 1 ;
           while (teller2 < teller)
                  {
                        printf("%d", uitkomst2[teller2]);
                        teller2 = teller2 + 1 ;
                  }
   return EXIT_SUCCESS;
        }
/*c----------  end of function main  ---------- */

It working now only not good.
4 gets now the answer 10 where it must be 100

Roelof

That's because you divide by 2 before trying to convert the number (as the first line in your while loop). Don't do that.

Originally Posted by tabstop

That's because you divide by 2 before trying to convert the number (as the first line in your while loop). Don't do that.

Old joke....

A guy walks into the doctor's office and hooks his thumb over the edge of the desk.
He pulls out a claw hammer and whacks himself right on the thumb.

"Doc, it hurts like heck every time I do that"

The doctor replied: "Then don't do that!".

Oke,

I changed it to this:

Code:

/*
 *  * =====================================================================================
 *   
 *          Filename:  test2.c
 *    
 *          Description:  conventer from dec to 0101
 *       
 *          Version:  1.0
 *          Created:  14-05-11 10:03:25
 *          Revision:  none
 *          Compiler:  gcc
 *            
 *          Author:  Dr. Fritz Mehner (mn), [email protected]
 *          Company:  FH Südwestfalen, Iserlohn
 *               
 * =====================================================================================
  */

#include        <stdio.h>
#include        <stdlib.h>

int
main ( int argc, char *argv[] )
        {
            int nummer, uitkomst, teller;
            char uitkomst2[10];
            nummer = 2 ;
            uitkomst = 2 ;
            teller = 0 ;
            while (uitkomst > 0)
                {
                        uitkomst2[teller++]= uitkomst%2;
                        uitkomst = nummer /2 ;
                        nummer = uitkomst;
                        printf ("teller:%d  deling:%d uitkomst deling:%d  \n",teller, uitkomst%2, uitkomst);
                }
            printf ("teller is nu %d", teller);
            while (teller >  0)
                  {
                        printf("%d", uitkomst2[teller]);
                        teller = teller - 1;
                  }
   return EXIT_SUCCESS;
        }
/*c----------  end of function main  ---------- */

But i see something wierd.
The output is now this

Code:

teller:1  deling:1 uitkomst deling:1  
teller:2  deling:0 uitkomst deling:0  
teller is nu 241

So the loop is executed right but after that teller is a complete other number.

Roelof

That's because you forgot to print a new line after the number. teller is 2, then you print some uitkomst2 after it.

CommonTater

Is my programm good or are there more things I have to learn,
If not, I will try to change this to converting to a octal number.

Roelof

Hello,

I know that printf can do the job.
But because in chapter 1 this is not in the text I'm not allowed to use it.
But when looking at the prevoius exercises I have a idea how to do it.
And I think I have to adapt this source a little bit.

Roelof

Hello,

I adapted the script so it looks like this:

Code:

 *   
 *          Filename:  test2.c
 *    
 *          Description:  conventer from dec to 0101
 *       
 *          Version:  1.0
 *          Created:  14-05-11 10:03:25
 *          Revision:  none
 *          Compiler:  gcc
 *            
 *          Author:  Dr. Fritz Mehner (mn), [email protected]
 *          Company:  FH Südwestfalen, Iserlohn
 *               
 * =====================================================================================
  */

#include        <stdio.h>
#include        <stdlib.h>

int
main ( int argc, char *argv[] )
        {
            int nummer, uitkomst, uitkomst3, uitkomst4, teller;
            char uitkomst2[10] ;
            nummer = 21 ;
            uitkomst = 21 ;
            teller = 0 ;
            while (uitkomst > 0)
                {
                        uitkomst3 = (uitkomst % 16) ;
                        if (uitkomst3 >=10)
                        {
                         uitkomst4 = uitkomst3 + 55 ;
                        }
                        else
                         {
                           uitkomst4 = uitkomst3 + 48 ;
                                }

                        uitkomst2[teller++]= uitkomst4;
                        uitkomst = uitkomst /16 ;
                }
             printf ("Het getal %d is octal ", nummer);
             while (teller >  0)
                  {
                        printf("%c", uitkomst2[teller-1]);
                        teller = teller - 1;
                  }
   return EXIT_SUCCESS;
        }

and Commentator thanks that you would be a friend.

Roelof