if I wanted to print out a phrase how would I go about doing that?
this code only allows me to print up until a space comes in to play. Do i have to incorporate some kind of loop?Code:int main() { char string[100]; printf("Enter Phrase\n"); scanf("%s",string); printf("%s\n", string); return 0; }
scanf stops at white spaces. You need to use fgets() for that.
1. Get rid of gets(). Never ever ever use it again. Replace it with fgets() and use that instead.
2. Get rid of void main and replace it with int main(void) and return 0 at the end of the function.
3. Get rid of conio.h and other antiquated DOS crap headers.
4. Don't cast the return value of malloc, even if you always always always make sure that stdlib.h is included.
Your query begs the question: you (seem to) believe that all the things you typed in at the prompt exist in the variable "string". But that is not the case -- your problem isn't with output, but with input. scanf (using %s) will not read in something with a space in it. You need to either ditch the %s in favor of %[, or ditch scanf in favor of fgets.
ok i have not been taught fgets yet so i will brush up on that thanks
Then you should read up on scanf. You can make it read past whitespace. man page (click)Originally Posted by camel-man
While it's true that %s stops on white space, you can scanf scan for pretty much anything you want.
Quzah.
Hope is the first step on the road to disappointment.
As already suggested... read the docs for scanf()....Code:int main() { char string[100]; printf("Enter Phrase\n"); scanf("%[^\n]",string); <--- note the bold face type... printf("%s\n", string); return 0; }
