my problem is when i compile it in my gcc compiler(gcc count.c -o count)Code://counting no:characters #include <stdio.h> main() { int c; for(c=0;getchar()!=EOF;c++) ; printf("%d",c); }
the program keeps on taking characters as input. thats all. does nothing. havn't even printing any number........i don't understand whats wrong with this
You need to press CTRL-D (Unix/Linux/MacOS) or CTRL-Z (DOS/Windows) to signal an EOF.
This will cause the loop to exit, and print whatever is in c.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Plus you need to remove the semicolon after your for loop
hth
-nv
She was so Blonde, she spent 20 minutes looking at the orange juice can because it said "Concentrate."
When in doubt, read the FAQ.
Then ask a smart question.
guys thank u very much.im just beginner....these may seem silly to u .
