Thread: Help Please

Code:

void main ()
{
int count=0;
TRISD=0x00;
MEMCONbits.EBDIS=1;
while(1)
{
if(count>8)
count=0;
switch(count)
{
case 0:
PORTD=0x00;
break;
case 1:
PORTD=0x01;
break;
case 2:
PORTD=0x03;
break;
case 3:
PORTD=0x07;
break;
case 4:
PORTD=0x0f;
break;
case 5:
PORTD=0x1f;
break;
case 6:
PORTD=0x3f;
break;
case 7:
PORTD=0x7f;
break;
case 8:
PORTD=0xff; // 0b11111111 , 255
break;
}
Delay10KTCYx(0);
count++;
}
}

Can you please tell me what this code is doing?

It is running around in a circle, counting from 0 to 8 and setting bits on a port.

Pretty useless really... unless that port connects to something.

If you want to know what the individual parts of the code ... switch(), if() etc. are doing... grab any good C language manual and look them up.

Thank you ,
you r righr since the port is connected to an LED

Originally Posted by KABIDI

Thank you ,
you r righr since the port is connected to an LED

Ok... so what do I win?

Progressively turning on LEDs until all eight are lit. Then turning all off and starting over.

Code:

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