Hi,
I've a two-dimensional character array, initialized as follows:
How to count number of strings present in this array?Code:char *valid_help_str[] = {{"help"},{"help add queue"},{"help add queue default"},{"help add queue basic"},{"help add queue medium"},{"help add queue advanced"}};
Thank you
If the array is in scope, you can do this
This does NOT work if you pass the array to a function, and try to do it inside the function.Code:size_t numElements = sizeof(valid_help_str) / sizeof(valid_help_str[0]);
You can add some newlines to your array you know, so we don't have to scroll horizontally as well.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
You can find the size of the array and divide it by the size of a char pointer:
The output from this program is "Number of elements = 6" which is expected.Code:#include <stdio.h> int main( void ) { char *valid_help_str[] = { "help", "help add queue", "help add queue default", "help add queue basic", "help add queue medium", "help add queue advanced" }; printf( "Number of elements = %lu\n", sizeof( valid_help_str ) / sizeof( char * ) ); return 0; }
Kevin
Since you are simply assigning string constants, there should be no reason to count anything... you should already know how many strings *you programmed* into the array.Originally Posted by sangamesh
