I am trying to find how do I find what output does it produce?
When I entered the following information in the complier nothing happens. Should I not enter the following code in the complierCode:int funA(intx); int main() { int a,b,c; a=5; b=5; c= funA(b); printf(%d %d %d,a,b,c); return 0; } int funA(int m) { return m*m; }
Last edited by intimidator; 04-23-2011 at 02:42 PM.
no compiler will compile that code for you. where are the semicolons? and how about including some header file for printf?
"All that we see or seem
Is but a dream within a dream." - Poe
My mistake I forgot the semicolons but, with the semicolons it will not compile
Programming languages like C have formal and very specific grammars. If you make any mistakes in the source code, the program will not compile. (As compared to human languages where we "get" what someone is trying to say, even though it may not be grammatically correct!)
You have three mistakes you need to address. The first is the failure to include a required library for the printf statement. The second is the argument in the funA prototype. And the third is the printf statement - the format string needs to be enclosed in quotes.
Having said all that, you should be able to "bench test" the program and step through it yourself and find the answer you're looking for!
Kevin
"Syntax error"Originally Posted by intimidator
that should do itCode:int funA(int x); int main() { int a,b,c; a=5; b=5; c= funA(b); printf("%d %d %d\n",a,b,c); return 0; } int funA(int m) { return m*m; }
When I try to compile the output camel-man posted I would see the black screen pop up but then it goes off screen and nothing happens.
Before the end of the main function, add
KevinCode:system("PAUSE");
