char[][] instead of char*[] in calling a function?

[mishoo123]

Hi All,

I have a function that takes 'char *[]' as parameter:

void myFunc(char *mystrings[]){}

In order to call it I need to create an array of 'char *' and call it. (with malloc and all)

Is there anyways to call this function with char[][] instead of char*[]? Something like this:

char mystring[2][20];

strcpy(mystring[0], "This is first line");
strcpy(mystring[1], "This is second line"); 
myFunc(mystring);

I've tried myFunc(*mystring) and myFunc(**mystring) already.

Thanks

[laserlight]

Is there anyways to call this function with char[][] instead of char*[]?

Not directly since an array of arrays is converted to a pointer to an array, not a pointer to a pointer. If necessary you could create an array of pointers, get those pointers to point to the first elements of those inner arrays, then pass the array of pointers which will be converted to a pointer to a pointer.