Thread: Float function prototype inside main?

Hi,
I'm trying to write a code for square using function. However I get the error when I declare the function prototype outside (similar to what I do for int functions), While It works fine when I declare the float function prototype inside main. Why it differ from int function? and Do I need to write prototype in every function where I need to call Square.

Working Code:

Code:

#include <iostream.h>
#include <stdlib.h>
#include <stdio.h>
#include <math.h>

int main( )

{
float square(float x) ;
float a, b ;
	printf ( "\nEnter any number " ) ;
	scanf ( "%f", &a ) ;
	b = square ( a ) ;
printf ( "\nSquare of %f is %f", a, b ) ;
}

float square ( float x )
{
float y ;
y = x * x ;
return ( y ) ;
}

Code Not working (With prototype outside main)

Code:

#include <iostream.h>
#include <stdlib.h>
#include <stdio.h>
#include <math.h>

int main( )
float square(float x) ;

{

float a, b ;
	printf ( "\nEnter any number " ) ;
	scanf ( "%f", &a ) ;
	b = square ( a ) ;
printf ( "\nSquare of %f is %f", a, b ) ;
}

float square ( float x )
{
float y ;
y = x * x ;
return ( y ) ;
}

Oops, yes. Got it. I was declaring prototype below main(). It should be above. Much thanks!