Thread: structures and pointers and members

Code:

struct dictionary {
       struct wordPair ** data;
       int nbwords;
       int size;
} *d;

That's a pointer to a pointer. I doubt that's what you want. But on the off chance it is, you should familiarize yourself with parenthesis. Or just pretend it's an array:

Code:

d->data[ X ]->englishWord;

Quzah.

Make things easy - use typedef to create pointer types to your structures - then you don't get hung up in pointer notation (as much):

Code:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

typedef struct wordPair {
    char *englishWord;
    char *foreignWord;
} WordPair;

typedef WordPair *WordPairPtr;

typedef struct dictionary {
    WordPairPtr data;
    int nbwords;
    int size;
} Dictionary;

typedef Dictionary *DictionaryPtr;

int main( void )
{
    /* allocate one dictionary structure */
    DictionaryPtr newDictionary = ( DictionaryPtr )malloc( sizeof( Dictionary ) );

    /* allocate word pair structure */
    newDictionary->data = ( WordPairPtr )malloc( sizeof( WordPair ) );

    /* initialize our new dictionary structure */
    newDictionary->data->englishWord = ( char * )calloc( 10, sizeof( char ) );
    strcpy( newDictionary->data->englishWord, "Hello" );

    newDictionary->data->foreignWord = ( char * )calloc( 10, sizeof( char ) );
    strcpy( newDictionary->data->foreignWord, "Bonjour" );

    newDictionary->nbwords = 1;
    newDictionary->size    = 1;


    /* use it */
    printf( "\"%s\" translates to \"%s\"\n",
            newDictionary->data->englishWord,
            newDictionary->data->foreignWord );


    /* free the memory - note we need to do a deep free */
    free( newDictionary->data->englishWord );
    free( newDictionary->data->foreignWord );
    free( newDictionary->data );
    free( newDictionary );

    return EXIT_SUCCESS;
}

Originally Posted by kmess

Make things easy - use typedef to create pointer types to your structures

People who typedef pointers need to be bludgeoned.

Quzah.