Thread: Typing decimal number and cover it binary number!

Hey everyone!
I am looking for a genius who can help to solve my very easy problem!)

My kinda homework is: Type a decimal number and the C should spit it out as binary.

e.g. 15 (decimal)-> 1111 (binary)

1. I'd create a mask c = 0X800
2. I would use the operator & to compare the typed number and the mask.
3. if the value = 0, print 0 and Shift mask 1 to right
4. Otherwise print 1 Shift mask and number 1 to right

I am playing with this already for hours.... just no positive result.
thanks for help and tips.

Code:

#include <stdio.h>

void main ()

{
        unsigned short int number; //Typed Number
 	unsigned short int b = 0x8000; // Mask

	
	
	printf ("Pleae type a postive number: ");
 	scanf ("%d", &number);
	 
	


 if ( number == 0 )
 { 	printf ("\nResult: 0000.0000.0000.0000");
 }       
      
 

 else if ( number != 0 )
 {


   while ( number & b != 0 );
   { 

    printf ("0");
	b = b >> 1;
   }


   while ( number & b != 0);
   {

   printf ("1");
   b = b >> 1;
   number = number >> 2;


   }
 
  
 }



 
	getchar ();
	getchar ();





}

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