Thread: Very simple Function using printf()

Originally Posted by Salem

> remove the & symbols and have it read
You need the & in these cases.

> but once I start messing with the format specifiers the output goes mental. What am I doing wrong?
Well how many things did you change from 'int' to 'double'?
And how many formats did you change from %d

Note that to scanf a double, you need "%lf", but to print it you only need "%f"

Post an example which doesn't work, if you're still stuck.

Here's my code with the ints changed to doubles and %d changed to %lf (or just %f)

Code:

#include <stdio.h> 
 
 void printfunc(double, double);
 
 int main(void)
 {
     int dub1, dub2;
     
     printf("Enter two decimal integers.\n");
     scanf("%lf %lf", &dub1, &dub2);
     printfunc(dub1, dub2);
     printf("Cheerio for now.\n");
     
     getchar();
     getchar();
     
     return 0;
 }
 
 void printfunc(double a, double b)
 {
      printf("%f %f\n", a, b);
      }

Adding two float values of 1.2 and 2.2 gives a printed output of 1073846681.000000 and -1717986918.000000