Thread: newline loop

Code:

#include <stdio.h>
#include <math.h>

int isprime(int n); 

int main(void)
{
int i; 
int count=1; 
printf( "The prime numbers from 1 to 1000 are \n" );
for ( i = 2;i < 1000;i++){
	if (isprime(i) && count%10!=0)
		printf("%d\t",i);
		count++;
	if (isprime(i) && count%10==0) 
		printf("%d\n",i);
		count++;
}}
int isprime( int n )
{
int sroot = sqrt(n);
int i;
for ( i = 2;i <= sroot;i++){
	if (n % i == 0)
		{return 0;}
	}
return 1;
}

i want a newline to be created after every 10th prime number and the if statements for int count do not work. Suggestions?

count % 10 can give you from 0-9 only.
You need count % 11.
And don't just tell it's not working. How it's not working!?

You don't need to test twice.
If count variable is supposed to keep track of number of prime printed, it should start from zero. Isn't it?

Code:

count = 0;                                       
for ( i = 2;i < 1000;i++){
	if (isprime(i)) {
		printf("%d",i);
		count++;
        }
	if ( count%11 ==0)  {
		putchar('\n');
        } else {
               putchar('\t');
       }
}
printf("%d primes!\n",count);