Thread: c program to debug

Code:

#include<stdio.h>
#include<conio.h>
void disp(int *);
void show(int *);
void main()
{
  int i;
  int marks[]={55,65,75,56,78,78,90};
  clrscr();
  for(i=0;i<=6;i++)
   disp(&marks[i]);
 getch();
}
void disp(int *n)
{
 show(&n);
 //printf("\n%d",*n);
}
void show(int *m)
{
 printf("\n%d",**m);
}

i have to print the contents of array but it is not working.
please help me.
and it is mandatory to use show() function

You do not need pointers and addresses to disply array contents...

It is just silly to write a function that does nothing but call another function. Call show() function directly.

Inside disp(), call show() like this: show(n)
Inside show(), use: printf("\n%d",*m) (single '*')