I am basically saying as long as the position in the array is not NULLCode:void strCase(char s[]) { int i; while (s[i] != NULL) { s[i] = toupper(s[i]); i++; } }
make the character a capital
but why am I not allowed to compare an integer (i) and a pointer (Null)??
[Warning] comparison between pointer and integer
NULL should only be used in pointer context because it's often defined as ((void*)0). What you're checking for is the null character ('\0'):
The specific meaning of your error is that char is an integer type and NULL is a pointer type. The warning says that you're probably not doing what you think you're doing, which is correct.Code:while (s[i] != '\0')
My best code is written with the delete key.
I got it to work but it still isn't capitalizing all my letters not sure why :\
Try initializing i.
where would I initialize 'i' in my code??Originally Posted by anduril462
When I take in the input or when I re-display it?
Presumably you want your i variable to have a defined value before you enter the loop. This value is probably 0.
You SHOULD initialize ALL variables before you use them.
Some instructors, want them initialized when you declare them.
Tim S.
now in the code below would this work for initializing i. I did it after declaring it
also using a while loopCode:int strCase(char s[]) { int i; for (i=0; s[i]!='\0';i++) s[i] = toupper(s[i]); }
Code:int strCase(char s[]) { int i=0; while(s[i]!='\0') { s[i] = toupper(s[i]); i++; } }
Last edited by cprogrammer1980; 03-25-2011 at 12:03 PM.
You presently have two near identical threads running... Pick ONE and stay with it...
Agreed -> capitalizing only first letter in strings??
Closed.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
