Thread: c linked list question.

I have the following question. My code is given below. Two problems I'm having with is:
1.How can I link the alphabets without using the arrays? Maybe use a for loop?
2.How to reverse the order of the linked list

Using the following struct:
typedef char DATA;
struct node
{
DATA d;
struct node * next;
};

Write a program to build a single linked list using a loop. Your list should be ordered so
that the last item added is at the beginning of the list

note: I did not use typedef in my code as I'm new to structures and it just confuses me at the moment

Code:

#include <stdio.h>
#include <stdlib.h>	/*for malloc()*/
#include <string.h>

int main()

{
	struct node{
	char d[2];
	struct node *next;			/*pointer to next structure*/
	};

	char *node[26]={"A","B","C","D","E","F",
					"G","H","I","J","K","L",
					"M","N","O","P","Q","R",
					"S","T","U","V","W","X",
					"Y","Z"};

	struct node *first_item;		/*pointer first_item to first structure*/
	struct node *current_item;
	struct node *new_item;
	int index=0;

	/*allocating memory for first structure*/
	first_item=(struct node*)malloc(sizeof(struct node));
	
	/*creating first structure*/
	current_item=first_item;

	/*fill the structures*/
	while(index<26)
	{
	strcpy(current_item->d,node[index]);

	index++;
	
	if (index<26)
		{

		new_item=(struct node*)malloc(sizeof(struct node));
		current_item->next=new_item;		/*set the address of new_item to pointer next*/
		current_item=new_item;
		}
	else
		{
		current_item->next=NULL;
		break;
		}
	
	}

	/*display the results*/

	current_item=first_item;
	index=1;
	while(current_item)
	{
		printf("Structure %d: ",index++);
		printf("%s\n",current_item->d);
		current_item=current_item->next;
	}



	getchar();
	return(0);
}