Thread: Comparing string arrays

I'll post an example in an edit to this post.

Code:

#include <stdio.h>
#include <ctype.h>

#define SIZE 100

int main() {
  int i, n;
  char s[SIZE]="";
  char ch;
  printf("\n\nEnter some letters and numbers, and etc. Only letters will go into the array s[]\n");
  i=0;
  while((ch=getc(stdin)) != EOF) { //EOF is Ctrl+Z
    if(isalpha(ch)) {
      s[i++]=ch;
    }
  }

  printf("\n%s", s);

  printf("\n\n\t\t\t     press enter when ready");
  (void) getchar(); 
  return 0;
}

variable++ increments the variable by one.

Yes, you should use a char array.

Originally Posted by Adak

I'll post an example in an edit to this post.

Code:

  char ch;
  printf("\n\nEnter some letters and numbers, and etc. Only letters will go into the array s[]\n");
  i=0;
  while((ch=getc(stdin)) != EOF) { //EOF is Ctrl+Z

The value EOF cannot be stored in a char. It is a negative integer type, that holds no char representable value.


Quzah.