Need help with temperature conversion program

[Aequitas]

this is what i have so far later i will add a step but 'farn' returns a large number like 2 million or something

#include <stdio.h>

int main(void)
{

	int index = 0;
	double tempc;
	double farn = 0;
	
/*°C = (°F - 32) / 1.8 
°F = °C × 1.8 + 32*/

	printf("Enter temperature in celsius:");
	scanf("%d",&tempc);
	printf("------------------------------\n");
	while(index<=5)
	{
		farn= tempc * 1.8 +32;
		printf("|  %d  |   %d   |\n",tempc, farn);
		index++ ;
		
	}
		printf("------------------------------\n");
	
	return(0);
}

can anyone see why it isnt working?

[CommonTater]

Farn is a double value... but in your printf you are printing an integer...
Look up the formatting codes for printf() and adjust accordingly.

[Aequitas]

ok i tried that and replaced the second %d in printf("| %d | %d |\n",tempc, farn);
with %g, %lg, %lf, i tried everything and none of them worked, most gave me an incredibly small negative number

[Aequitas]

ah nvm, I changed tempc to an integar and it worked with %g to print the farn temp

ty for that i didnt realize the print depended on that

[whiteflags]

The scanf call is also wrong: You're required to pass the correct arguments and use the correct conversions in the format string. I'm sure "%lf" will work and then you can printf it with "%f".