Thread: C passing 2D arrays to function

Hi,

passing an array or a 2D array is causing me some trouble.

can you please check the way i am doin it?

Here is how i define my arrays and pass them:

Code:

///////////////////////////////////////////////////////////////////////////////////////
main.c
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include "NN3.h"

int main()
{
     real_T u[2][3] = {
                        {0.8147,    0.1270,    0.6324},
                        {0.9058,    0.9134,    0.0975}
                    };
    
     real_T D[1][3] = {0.7922,    0.6557,    0.8491};
                    
     real_T u_test[2][3] = {{0.9572,    0.8003,    0.4218}, 
                                {0.4854,    0.1419,    0.9157}
                         };
            
     real_T D_test [1][3] ={0.2785,    0.9575,    0.1576};
    
    
     y = NN3(u,*D, u_test, *D_test);

    
    return 0;
}
//////////////////////////////////////////////////////////////////////////////////////////

the function prototype is defined as:

Code:

 void NN3(const real_T eml_u[6], const real_T eml_D[3], const real_T
 eml_u_test[6], const real_T eml_D_test[3], real_T eml_y[3])

I dont want to change the function prototype. I would rather change the way i am passing the arrays in main.c

Thanks,

MAS

Originally Posted by Salem

Since your function only accepts single-dimension arrays, you can probably get away with passing your 2D arrays as pointers to the first element.

Say
NN3( &u[0][0],

Thank you.