help with c print specifiers

[newbc]

Hi have a question for one of my homework. I need to explain what is going on the printf statement i have figure all of them except for this two.

line 6	printf("%*.*f", 7, 2, num);
line 19	printf("%t%3f\n", num);

lets say num = 26.536

i know line 6 is the same as saying printf("7.2f"), but i looked on line but all the results i get are pointer declarations, etc.

line 19 im confused since \t is an escape sequence for a hor. tab right. but is just prints "%3f"

thanks for the help.

[nonoob]

Line 6: You forgot the %.
Line 19 The tab should be "\t". Not "%t"

[CommonTater]

Line 6 will print *.*f and line 19 will print %3f because it doesn't understand your formatting setups...

printf format identifiers.

For the first line to print 7 2 26.536 you would need printf("%d %d %.3f",7,2,num);

I'll let you figure the second one out on your own...

[nonoob]

No. newbc is using variable width/precision specifier '*'.

[CommonTater]

No. newbc is using variable width/precision specifier '*'.

Ok... this is new to me... Gonna have to look this one up...
(I spend most of my time working in windows and printf isn't a big part of my life)

[newbc]

yes line six is suppose to include the % sorry.