Thread: A noob need help

Im a noob in C and I got this simple code working..

Code:

#include <stdio.h>
#include <conio.h>
#include <string.h>

int main ()
{
    char str1[20]="burke",str2[20];
    
    printf("Dog's name?:");
    scanf("%s",str2);
    
    if (strcasecmp(str1, str2)==0){
    printf("Gratz you got it",str2);
    }
    else{
    printf("Wrong Answer!!!");     
    }
    
    getch();
}

My problem is what if instead of "burke" its "burke jr." in str1[20] coz somehow i can get it working. >.< been studying C for almost a week now I hope you guys can help me. and give me some tip,hint and advice

Code:

#include <stdio.h>
#include <conio.h>
#include <string.h>

int main ()
{
    char str1[20]="burke jr",str2[20];
    
    printf("Dog's name?:");
    scanf("%s",str2);
    
    if (strcasecmp(str1, str2)==0){
    printf("Gratz you got it",str2);
    }
    else{
    printf("Wrong Answer!!!");     
    }
    
    getch();
}

im getting Wrong Answer.

Read the docs for scanf()... it will stop assigning characters whenever it encounters a space...

Look at the documentation for other ways of reading characters from the keyboard to find one that will read until carriage return... fgets() gets() etc.

Originally Posted by Babkockdood

1. To use scanf, you need to put an ampersand in front of the second argument.
2. Use fgets(str2, sizeof(str2), stdin) to get strings from the user instead of scanf. fgets with stdin stops reading input when you enter a newline, scanf stops when you enter a space.

He doesn't want the ampersand (address of) for a string input... the array name already is a pointer.

But, yes, fgets is probably his best bet.

thanks guys. fgets and a simple format specifier for scanf works too as I did some research..

Code:

scanf("%[^\n]]s",str2)