Thread: How to allocate memory using void*?

This is how I allocate in main:

Code:

Ax r = (Ax)malloc(nr*sizeof(Tx));

And in function:

Code:

void* r = (void*)malloc(nr*d)

Ax is a pointer to a struct;
d = sizeof(Tx);

The function will return the "r" for which it is supposed to allocate memory.

The only bugaboo in that is allocating void* gives you a "typeless" blob of memory and from there you have to use a typecast every time you access it.

There is no penalty in allocating typed memory... all you're really doing is telling the compiler what to expect in that location so that you don't have to typecast.

I need that function to work for any type. I should have mentioned that in the OP.

Is the allocation correct?

yes, you don't need to case malloc() return value. because it's already returning void * type.
just make sure that memory allocated is enough for your type.