Thread: Second scanf call with char does not work

  1. #1
    Registered User
    Join Date
    Feb 2011

    Second scanf call with char does not work


    This is my first post to the forum, I have a question regarding the scanf function. My program seems to find a random value to use on the second scanf call in my program. I'm using scanf with a char on both occasions. It does not ask for user input on the second scanf function. How can I fix this, do I have to use something else than scanf?

    Here is my simple code so far:

    #include <stdio.h>
    #include <stdlib.h>
    int package_i;
    char internet, package, phone;
    float cost;
    main () {
        printf("Welcome to XYZ Cable Providers\nWould you like to subscribe to Internet? (Y or N): ");
        scanf("%c", &internet);
    if (internet == 'Y') {
    printf("Choose package 1, 2, or 3: ");
    scanf("%d", &package_i);
    switch (package_i) {
    case 1:
    cost = 15.99;
    case 2:
    cost = 21.99;
    case 3:
    cost = 25.99;
    printf("Your total cost is %.2f!", cost);
    printf("Would you like to subscribe to Home Telephone? (Y or N): ");  
    scanf("%c", phone);
    Thanks for the help,

    Last edited by madwizzy; 02-15-2011 at 09:55 PM.

  2. #2
    ATH0 quzah's Avatar
    Join Date
    Oct 2001
    You need to do something with the \n (newline character) that is being entered. The FAQ should give you various ways to handle it. You press Y and then hit ENTER, which is 2 characters. You only store one, and the other is left in the input stream, and picked up by the next scanf call.

    Hope is the first step on the road to disappointment.

  3. #3
    Registered User
    Join Date
    Sep 2006
    Before a scanf() to get a char, be sure the input stream is clean. No you can't use fflush(stdin).

    You can add getchar() after the scanf() which is BEFORE the scanf() for the getchar(). This problem sometimes will afflict other scanf() formats, as well. Usually, it's the one's for a char.

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