Thread: Uncle! - How can I cast a string as int?

I've got a char[] pointer:
How do I convert the "43" to an integer 43?

I need x to equal the integer that the string represents.

I keep getting the location or the ascii value or some other number that doesn't make sense to me.

I've tried every use of * that I could think of.

Code:

int main(int argc, char *argv[])
{
	int i=0;
	int x;
	char *token[4];
	token[0] = "43";
	token[1] = "72";
	token[2] = "17";
	token[3] = "9";
	
	for(i=0;i<4;i++)
	{
		x = (int)(*token)[i];
		printf("\n%d", x);
	}
	return 0;
}

quzah - thanks but if it can do it, I sure can't figure out how.


-----------
QUOTE "Hundreds of thousands of dip........s can't be wrong."
Oh yes they can

This is a *great* forum!
I finally found it in an older thread
atoi

You should use strtol for better error handling.

thanks