when i wrote this a took nothing
Code:#include <stdio.h> int main( ) { int x = 10, y = 20 ; if ( x == y ) printf ( "\n%d %d", x, y ) ; system("pause"); }when i wrote this i took the correct result.I think it should give the correct result in first beacuse of ; near if expression.What's my fault?Code:#include <stdio.h> int main( ) { int x = 10, y = 20 ; if ( x == y ) ; printf ( "\n%d %d", x, y ) ; system("pause"); }
> if ( x == y ) ;
This is the same as
You can indent the printf statement, but it won't make it part of the if statement.Code:if ( x == y ) { // there isn't anything to do here }
Oh, and for consistent behaviour across all platforms, put your \n at the end of the format string.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
thanks a lot i understand my fault
When's the last time that 10 = 20?Code:#include <stdio.h> int main( ) { int x = 10, y = 20 ; if ( x == y ) printf ( "\n%d %d", x, y ) ; system("pause");
X does not equal y ... therefore the printf statement is never executed.
It worked perfectly... however; not in the way you expected.
Last edited by CommonTater; 01-17-2011 at 08:02 AM.
