Plasea help me!!!!

[hakimstm1b]

The Pictograph 3 below shows the number of students in STM 2A class. STM 2B has 4 students more than STM 2A. If STM 2C has 75% students more than STM 2A, calculate the total of students in these three classes.

STM 2A = 36 student


anyone no how to solve this?

[\007]

The Pictograph 3 below shows the number of students in STM 2A class. STM 2B has 4 students more than STM 2A. If STM 2C has 75% students more than STM 2A, calculate the total of students in these three classes.

STM 2A = 36 student


anyone no how to solve this?

If STM 2A = 36 student then...

STM 2A = 36 student
STM 2B = 40 students (4 more than 2A)
STM 2C = (75% of 36)+36 students


Total number of students all together = add A, B and C together. No?

[hakimstm1b]

thank

[\007]

No problem. I don't see how this relates to C, but good luck and if you need any more math help ask around but try to find an off topic thread or something. I am sure a lot of people around here can help.

[hakimstm1b]

If [ a ] = 5 cm , and [ b ] = 3a cm , find [ a + b ]


can help me?

[Bayint Naung]

#include <stdio.h> // for printf..

int main(void) {
int a,b,c;
a = 5;
b = 3 * a;
c = a + b;
printf("%d\n",c);
return 0;       // success!
}

[\007]

Great-- just keep in mind the units are cm and may need some decimal points and units tacked on, but good job.

[hakimstm1b]

thank again

[hakimstm1b]

so the answer will be 8a

[\007]

I don't know where you would get that from.

a = 5
b = 3*a (= 15)
c = a+b (5+15)

Last time I checked 15+5 is 20.

[hakimstm1b]

A 8
B 10
C 8a
D 5

only this answer have....