1. ## Plasea help me!!!!

The Pictograph 3 below shows the number of students in STM 2A class. STM 2B has 4 students more than STM 2A. If STM 2C has 75% students more than STM 2A, calculate the total of students in these three classes.

STM 2A = 36 student

anyone no how to solve this?

2. Originally Posted by hakimstm1b
The Pictograph 3 below shows the number of students in STM 2A class. STM 2B has 4 students more than STM 2A. If STM 2C has 75% students more than STM 2A, calculate the total of students in these three classes.

STM 2A = 36 student

anyone no how to solve this?
If STM 2A = 36 student then...

STM 2A = 36 student
STM 2B = 40 students (4 more than 2A)
STM 2C = (75% of 36)+36 students

Total number of students all together = add A, B and C together. No?

3. thank

4. No problem. I don't see how this relates to C, but good luck and if you need any more math help ask around but try to find an off topic thread or something. I am sure a lot of people around here can help.

5. If [ a ] = 5 cm , and [ b ] = 3a cm , find [ a + b ]

can help me?

6. Code:
```#include <stdio.h> // for printf..

int main(void) {
int a,b,c;
a = 5;
b = 3 * a;
c = a + b;
printf("%d\n",c);
return 0;       // success!
}```

7. Great-- just keep in mind the units are cm and may need some decimal points and units tacked on, but good job.

8. thank again

9. so the answer will be 8a

10. I don't know where you would get that from.

a = 5
b = 3*a (= 15)
c = a+b (5+15)

Last time I checked 15+5 is 20.

11. A 8
B 10
C 8a
D 5