You don't understand C pointers.
You don't understand C memory allocation.
You don't understand C pointer accessing.
The correct access to an element in a stringarray (char**) is StrArr[i] not StrArr+i, see:
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BillyTKid, from what I understand I can use the the StrArr+i to move up the array. I've seen some examples using this method.
Well... there is a reason C provides the [] indexing of arrays... The array[x] syntax takes the size of the array elements into account. The array+x method does not...Originally Posted by godmoney
Just because you can do something does not mean you should.
> The array[x] syntax takes the size of the array elements into account. The array+x method does not...
Mmm, want to try that again?
This prints 4, as it should.Code:#include <stdio.h> int main() { int arr[10] = { 1, 2, 3 }; arr[3] = 4; printf("%d\n", *(arr+3) ); return 0; }
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Ummmm.... maybe not?
Sure, that allows you to obtain a pointer that points to a different element in the array, i.e., the element at index i. However, to actually access the element at index i, you must dereference the pointer result, i.e., StrArr+i should be *(StrArr+i). But *(StrArr+i) is equivalent to StrArr[i], so you might as well use StrArr[i].
Consequently, just writing StrArr+i is not wrong because the "array+x method does not" take "the size of the array elements into account": it is wrong because it does not access the element that you want to access.
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