sorting program

[jk]

I need to make sorting program with out using array, Sort commend.
I must use pointers, call by reference, and call by value.
I didn't finish the rest of the part, since there's something wrong with my function call.
I think my function call for read5 is wrong, but I don't know how to fix. Since, I have to make function read5 to get input.
How can I make function call for read 5?



/* Program that utilizes simple functions illustrating call-by-reference and call-by-valye */

#include <stdio.h>

double read5(double*, double*, double*, double*, double*);
double sort5(double*, double*, double*, double*, double*);
double print5(double*, double*, double*, double*, double*);

int main(void)
{ /* begin main */
/* Declaration */
int checknum = 1;

/* Check Scanf */
while(checknum > 0)
{ /* start while */
if (checknum == 0)
{ /* begin if */
printf("Ends Program");
checknum = -1;
} /* end if */
else
{ /* begin else */
checknum = read5(double*, double*, double*, double*, double*);
sort5(double*, double*, double*, double*, double*);
print5(double*, double*, double*, double*, double*);
} /* end else */

} /* end while */

}


double read5(double *i, double *j, double *k, double *l, double *m)
{
int check;

check = scanf(&i, &j, &k, &l, &m);
return check;
}

} /* end read5 */

double sort5(double *u, double *v, double *w, double *x, double *y)
{
int count, count2, count3;
double numsave, numsave2, numsave3, numsave4;

for(count=0; count <= 10; ++count)
{
if(u <= v)
{
numsave = *u;
}
else
{
numsave = *v;
}

if(w<=x)
{
numsave2 = *w;
}
else
{
numsave = *x;
}


}
}

[quzah]

If you're reading into an address that is already a pointer, using the scanf functions, just use its name without the address-of operator:

void read( double *ptr1, double *ptr2, double *ptr3, double *ptr4 )
{
    printf("Enter four floating point numbers: ");
    scanf( "%f %f %f %f", ptr1, ptr2, ptr3, ptr4 );
}

Quzah.