Thread: Function returning pointers

Please see the code below :-

insert

Code:

int main(){
    int *p;
    int *fun();
    p = fun();
    printf("Value of i %d" , *p);
    getch();
    return 0;
}

int *fun(void){
    int i = -214223;
    return (&i);
}

When i print the value of i in main , i expect it to give a garbage value since the variable i is local to fun.
But actually its giving me the correct value.
How is this possible....Please help

Undefined behavior can mean anything. including giving you the result that you expect.
you could try to say call any function before printing the value with printf().

The variable was local, but after the function finished the memory was given back to the system, but given there is so little going on in this program.. when the location was called again the value had been unchanged because no other function needed the space yet.

That's my assumption.

Try to call some other functions and do stuff before printing the value of i and see if you get garbage.

yes when i actually call some other functions before printf() , it does give me a garbage value.

That would verify my thoughts.