The program is suppose to look thought str and see if part can be found inside. problem is that it doesnt do that. can someone help me fix it?
Code:#include <stdio.h> #include <math.h> #include <string.h> int main () { char str[][17] = { "ATTCGCTTATTCCGAC" , "AAGCGCTAACCGCTAG" , "CAGCGCAAACGCCGTT" , "GCGCTCAAAGGCTTAA" }; char part[17]="GCGCA"; int n; for (n=0 ; n<4 ; ++n) { if (strcmp (str[n],part, 5) == 0) { printf ("found %s\n",str[n]); } } }
Did you compile it?
What were the error messages - something about strcmp() not having 3 parameters perhaps?
Did you perhaps intend to use strncmp() ?
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
Sounds like a job for strstr().
If you understand what you're doing, you're not learning anything.
i noticed that and fixed it but it still doesnt print anything.Originally Posted by Salem
Perhaps you were thinking of strstr then.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
i am not allowed to use strstr. but i was told i can use points. the problem it i have no idea how to use pointers in this problem
Your code is required to find a substring, but you are only comparing the strings.
Try writing down on paper how you would find if any of the str[n]'s contain a substring that is equal to part. In particular, ponder the difference between "find substring" and "compare strings".
Did you check manually to see if your short code actually exists in the longer ones?
Perhaps they want you to fake strstr() by calling strncmp() in a loop.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
